Jagdeep a fire man while throwing water on a fire of the burning house noticed a women in the first floor crying for help the first floor is at height of 20 metre above the ground jagdeep fix the staircase in such a way that one end of staircase touches the top of 1st floor and the other end makes an angle 30 degree with ground jagdeep goes to first floor by staircase and saves the woman calculate the distance travelled by jagdeep
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The wall of the building, the ground and the staircase form a right angled triangle.
Let x = the distance traveled by the jagdeep (hypotenuse)
Sin 30 = 20/x
⇒ x = 20/Sin 30 = 40
So, the jagdep traveled 40m
See the attached image.
Let x = the distance traveled by the jagdeep (hypotenuse)
Sin 30 = 20/x
⇒ x = 20/Sin 30 = 40
So, the jagdep traveled 40m
See the attached image.
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Varsha05:
Simple...thank you
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Let the distance traveled by Jagjeet be X
Thus According to question
Stairs will make a right angles triangle with the building
Thus In the right angle triangle
Sin 30 = 20/ x
Thus X = 20 * 2 = 40 m
Thus distance traveled by jagjeet is 40 m
Thus According to question
Stairs will make a right angles triangle with the building
Thus In the right angle triangle
Sin 30 = 20/ x
Thus X = 20 * 2 = 40 m
Thus distance traveled by jagjeet is 40 m
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