Jagdish has three more ₹ 5 coins than ₹ 10 coins . If he has ₹ 195 worth of money in total , how many of each kind of coins of each does he have ?
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Answered by
156
Let the number of ten rupee notes= x
therefore , number of five rupee notes = x+3
Total money = 10*(number of ten rupee notes ) + 5 (number of five rupee notes)
= 10*x + 5*(x+3)
=10x +5x +15
=15x + 15
therefore ,15x+15 = 195
15x = 195 - 15
15x = 180 or x = 180/15
x=12
Therefore number of ten rupee notes= 12
hence , number of five rupee notes
= x+3=12 +3=15
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therefore , number of five rupee notes = x+3
Total money = 10*(number of ten rupee notes ) + 5 (number of five rupee notes)
= 10*x + 5*(x+3)
=10x +5x +15
=15x + 15
therefore ,15x+15 = 195
15x = 195 - 15
15x = 180 or x = 180/15
x=12
Therefore number of ten rupee notes= 12
hence , number of five rupee notes
= x+3=12 +3=15
Hope this helps you!!
Thank You!
!Cheers !!
If you are satisfied please mark my answer as the brainliest!
Answered by
13
Step-by-step explanation:
Let the number of Rs 10 note = x
Number of Rs 5 note = x+3
Total value of the sum = 10*x + 5(x+3) which is equal to 195 as per question .
or , 10x + 5x + 15 = 195
or ,15x = 180
or , x = 12
Number of Rs 10 note = 12
Number of Rs 5 note = 12 + 3 = 15 .
2 - Let the three consecutive even numbers are 2(x-1) , 2x and 2(x+1)
as x-1 , x and x+1 are consecutive natural number .
according to question,
2(x-1) + 2x + 2(x+1) = 96
or , 6x = 96
or , x = 16
Putting x = 16 , we get numbers as 30 , 32 and 34 .
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