Math, asked by Anupam1169, 11 months ago

Jagrutiben deposits Rs.44,000 at 9.5% rate of interest for 2 years. At last how much compound interest will she get?

Answers

Answered by srijanv162002
0

Answer:

CI = 4180 rs

Step-by-step explanation:

P= 44000 rs

R = 9.5 %

t= 2years

A = p(1+r/100)^n

A = 44000(1+9.5/100)^2

A = 44000×1+19/200

A= 44000×219/200

A = 220× 219

A = 48180 rs

CI = A- P

CI = 48180 - 44000

CI = 4180 rs

Answered by Anonymous
0

Answer:

4180

Step-by-step explanation:

Principal = P = Rs 44000 (Given)

Rate = R = 9.5 % (Given)

Time = T= 2 yrs (Given)

According to the formula of compound interest -

CI = p (1+r/100)`n

A = 44000(1 +9.5/100)²

A= 44000×219/200

A = 220× 219  

A = 48180

Thus, the amount is Rs. 48180

Compound Interest = Amount - Principal

CI = A- P

CI = 48180 - 44000

CI = 4180

Thus, the compound interest of Rs. 4180 will be received.

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