Question

Jai is standing on the top of a building of height 25m wants to throw his gun to veeru who stand on top of other building of height 20m at a distance 15m from building. For which horizontal speed of projection, it possible

Answer 1

Answer:

Final Answer :@= 3

That is,

Packet falls 20/3 m. before the friend.

Steps and Understanding :

1) We will find time taken by packet to reach the ground by vertical equation of motion.

Let the angle made by speed with vertical be theta.

S(y) = 30m

a(y) = 10m/s^2

u(y) =125/3 cos theta

See pic 1 for calculation.

2) We will find horizontal distance from cliff by horizontal equation of motion.

a(x) = 0

u(x) = 125/3 sin (theta)

S(x) = x (say) horizontal distance from. cliff