Jai is standing on the top of a building of height 25m wants to throw his gun to veeru who stand on top of other building of height 20m at a distance 15m from building. For which horizontal speed of projection, it possible
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Answer:
Final Answer :@= 3
That is,
Packet falls 20/3 m. before the friend.
Steps and Understanding :
1) We will find time taken by packet to reach the ground by vertical equation of motion.
Let the angle made by speed with vertical be theta.
S(y) = 30m
a(y) = 10m/s^2
u(y) =125/3 cos theta
See pic 1 for calculation.
2) We will find horizontal distance from cliff by horizontal equation of motion.
a(x) = 0
u(x) = 125/3 sin (theta)
S(x) = x (say) horizontal distance from. cliff
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