Question

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Answer 1

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Answer 2

= (tanθ + 2)(2tanθ + 1)

= 2tan²θ + tanθ + 4tanθ + 2

= 2tan²θ + 5tanθ + 2

= 2(tan²θ + 1) + 5tanθ

we know sec²θ - tan²θ = 1

sec²θ = 1 + tan²θ

= 2 × sec²θ + 5tanθ

= 2sec²θ + 5tanθ