Question

Jaimin takes Rs. 10000 at 12% per year as rate of interest, for 2 years. How much interest he
has to pay at the end of two years?

Answer 1

Answer:

2400

Step-by-step explanation:

prt/100=10000×12×2/100 =2400

Answer 2

Step-by-step explanation:

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

Here,

principal (p)=10,000

Time period (t)=2 years

⠀⠀⠀⠀

Rate of interest (r)=12%

$\sf{\bold{\blue{\underline{\underline{To\:Find}}}}}$

How much interest he has to pay at the end of 2 years.⠀⠀⠀⠀

$\sf{\bold{\blue{\underline{\underline{Solution}}}}}$

Principal=10000

time=2

intrest=12%

so,

$\boxed{\underline{\underbrace{\mathcal\color{green}{S.I=\frac{p×t×r}{100}}}}}$

$\rightsquigarrow{\frac{10000×2×12}{100}}$

$\rightsquigarrow{\frac{\cancel{10000}×2×12}{\cancel{100}}}$

$\rightsquigarrow100×12×2$

$\bold\rightsquigarrow2400$

⠀⠀

$\sf{\bold{\blue{\underline{\underline{Answer}}}}}$

so,He has to pay at the end of the two year is 2400$⠀⠀⠀⠀