Question

Jaimin takes Rs. 10000 at 12% per year as rate of interest, for 2 years. How much interest he

has to pay at the end of two years?​

Answer 1

$\Large \sf \underline{\underline{\tt Understanding \: the \: question :}}$

We are given that Jaimin takes Rs. 10000 at 12% per year as rate of interest for 2 years.

So, we are given Principle, rate of interest and time as Rs. 10000, 12% per annum and 2 years respectively.

How much interest he has to pay at the end of two years?

We have to find Simple interest which Jaimin have to pay at end of 2 years.

$\Large \sf \underline{\underline{\tt Answer :}}$

Given :

• Principle, P = Rs. 10000

• Rate of interest, R = 12% p.a.

• Time, T = 2 years

To Find :

• Simple interest = ?

Solution :

We know that :

$\large \underline{\boxed{\bf{Simple \: interest = \dfrac{P \times R \times T}{100}}}}$

By putting values :

$\sf : \implies Simple \: interest = \dfrac{10000 \times 12 \times 2}{100}$

$\sf : \implies Simple \: interest = \dfrac{10000 \times 24}{100}$

$\sf : \implies Simple \: interest = \dfrac{2400\cancel{00}}{1\cancel{00}}$

$\sf : \implies Simple \: interest = 2400$

$\large \underline{\boxed{\bf{Simple \: interest = Rs. \: 2400}}}$

Therefore, Jaimin has to pay Rs. 2400 as interest at the end of 2 years.

Answer 2

Step-by-step explanation:

Understandingthequestion:

We are given that Jaimin takes Rs. 10000 at 12% per year as rate of interest for 2 years.

So, we are given Principle, rate of interest and time as Rs. 10000, 12% per annum and 2 years respectively.

How much interest he has to pay at the end of two years?

We have to find Simple interest which Jaimin have to pay at end of 2 years.

\Large \sf \underline{\underline{\tt Answer :}}

Answer:

Given :

Principle, P = Rs. 10000

Rate of interest, R = 12% p.a.

Time, T = 2 years

To Find :

Simple interest = ?

Solution :

We know that :

\large \underline{\boxed{\bf{Simple \: interest = \dfrac{P \times R \times T}{100}}}}

Simpleinterest=

100

P×R×T

By putting values :

\sf : \implies Simple \: interest = \dfrac{10000 \times 12 \times 2}{100}:⟹Simpleinterest=

100

10000×12×2

\sf : \implies Simple \: interest = \dfrac{10000 \times 24}{100}:⟹Simpleinterest=

100

10000×24

\sf : \implies Simple \: interest = \dfrac{2400\cancel{00}}{1\cancel{00}}:⟹Simpleinterest=

1

00

2400

00

\sf : \implies Simple \: interest = 2400:⟹Simpleinterest=2400

\large \underline{\boxed{\bf{Simple \: interest = Rs. \: 2400}}}

Simpleinterest=Rs.2400

Therefore, Jaimin has to pay Rs. 2400 as interest at the end of 2 years.