Math, asked by mounika1844, 8 months ago

jain wants to celebrate her daughters birthday. this time it was a prestige issue to her, as only last month her neighbor celebrated her son's birthday in a grand fashion. she borrowed two loans at simple interest, one for Rs.16000 at 5% per annum and the other for Rs.12000 at 5% per annum for the Same period. she paid Rs.7000 as total interest. what is the period for which she borrowed the money?

Answers

Answered by Jiyagurnani13
5

1st loan

Principle= 16000rs

rate= 5% (per annum)

time=?

interest= P×R×T/100

= 16000×5×T/100

= 160×5×T

= 800T

2nd loan

Principle= 12000rs

rate= 5% (per annum)

time=?

interest= P×R×T/100

= 12000×5×T/100

= 120×5×T

= 600T

given that-

interest1 + interest2 = 7000

800T + 600T = 7000

1400T= 7000

T= 7000/1400

T= 5

Hence,

He borrowed money for 5years.

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Answered by sweetyjindal1996sj
0

Answer:

Time period for which she borrowed money is 5 years.

Explanation:

Given

two loans

Loan 1 = Principal = 16000, rate = 5%

Loan 2 = Prinicipal = 12000, rate = 5%

total interest = 7000

to find : period for she borrowed money

Loan 1

Simple interest = ( principal × rate × time ) /100

Simple interest = (16000 × 5 × time) /100

Simple interest (S1) = 800 × time

Loan 2

Simple interest = ( principal × rate × time ) /100

Simple interest = (12000 × 5 × time) /100

Simple interest (S2) = 600 × time

S1 + S2 = 7000

(800 × time ) + (600 × time) = 7000

1400 × time = 7000

time = 7000/1400

time = 5

time period = 5 years

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