Math, asked by trepansingh25, 7 months ago

Jake's and his son's present ages are  j years and s  years respectively.Jake was 5 times as old as his son 2 years ago. up2years later, Jake's age will be 8 years more than three times his son's age.​

Answers

Answered by lalit4286
0

jake=42

jake of son=10

Step-by-step explanation:

suppose the jake age =x

suppose the jake of son=y

before the two year

(x-2)=(y-2)5

x-2 =5y-10

x-5y=-8 equestion… 1

after the two year

(x+2)=(y+2)3+8

(x+2)=3y+6+8

x-3y=12 equation …2

equation …1 and equation …2

x-5y=-8

x-3y=12

by the displacement method

-2y=-20

y=10

y=10 put the equation 1…

x-5y=-8

x=-8+50

x=42

jake=42

jake of son=10

I hope my answer is very…very nice

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