Question

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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :

seg DH ⊥ seg EF and seg GK ⊥ seg EF.

DH = 12cm, GK = 20 cm and

Area (ᐃDEF) = 300 cm ²

To find :

1. EF
2. Area (ᐃGEF)
3. Area ( square DGEF )

solution:

1 .

Area of a (ᐃDEF) = 1/2 × EF × DH

300=( 1/2)× EF × DH

EF = 50 cm

2.

ᐃDEF and ᐃGEF have the common base EF

therefore :

there areas are proportional to their corresponding sides.

area( ᐃDEF)/ area (ᐃGEF) = DH / GK

on putting values ,

area (ᐃGEF) = 500 cm ²

3.

Area ( square DGEF ) = area ( triangle DEF ) + area ( GEF )

= (300+ 500 )cm ²

= 800 cm ²

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