Math, asked by suyashdongre345, 6 months ago

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Answered by Anonymous
5

put x=1, in the eq

 {1}^{2}  - 3(1) + 2k = 0

1 - 3 + 2k = 0

2k - 2 = 0

2k = 2

k = 1

Answered by riyabante2005
2

Step-by-step explanation:

put x=1, in the eq

12 – 3(1) + 2k = 0

1-3 + 2k = 0

2k - 2 = 0

2k = 2

k = 1

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