Question

jaldi सै answer dedo iska please please ​

Answer 1

$\mathbb{\huge{\purple{Zia\: Dilliwali}}}$ $\huge\boxed{\large\boxed{\large\boxed{\mathbb{BRAINLIST!}}}}...$

Given,Total distance covered= x

km=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

 

Fare for next(x-1)km= 5(x-1)

 

A.T.Q

 

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

 

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y=

5+3=8

When x= 2, then y= 10+3=13

 

[Table & graph are on the attachment]

 

Now plot the points A(0,3), B(1,8), C(

2,13) on the graph paper and join them to form a line BC, which represents the

required graph of the linear equation

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