Math, asked by leishangthemthoibi2, 10 months ago

Jame's age is six times his son's age.Twenty years ago he was ten times his son age. Find their present age.​

Answers

Answered by Sanam3152
1

Sorry mate I dunno if my solution is correct but I tried my best

Attachments:
Answered by kvkeerthana
2

Answer:

Jame's age = 6x = 6 × 45 = 270 years

Son's age = x = 45 years

Step-by-step explanation:

Jame's age = 6x

Son's age = x

Twenty years ago:

Jame's age = 6x - 20

Son's age = x - 20

6x - 20 = 10(x - 20)

6x - 20 = 10x - 200

6x - 10x = -200 + 20

-4x = -180

x = -180/-4

x = 45

Jame's age = 6x = 6 × 45 = 270 years

Son's age = x = 45 years

Check ⇒

270 - 20 = 10(45 - 20)

250 = 450 - 200

250 = 250

L.H.S = R.H.S

Hence, verified.

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