James has an aquarium of capacity of 25 L. if he has filled 3/4 of the tank already. how many more litres of a water he needs to fill the aquarium?
Answers
Answer:
a.
height of water in the aquarium =
= volume of water filled / area of bottom of aquarium
= 60, 000 cm³ / (100 cm * 40 cm) = 15 cm
If the length and breadth given are the dimensions outside (external), then
height = 60, 000 cm³ / [ (100 - 2 * 0.4) cm * (40 - 2 * 0.4) cm ]
= 15.43 cm
b) if given dimensions are internal dimensions of aquarium. then:
(there is no top lid)
external Volume of aquarium = (100 + 0.4*2)(40+0.4*2)(25+0.4*1) cm³
= 1, 04, 461.056 cm³
Internal volume = 100 * 40 * 25 = 1,00,000 cm³
Volume of the glass material in the aquarium = 4, 461.056 cm³
Weight of the aquarium = 4, 461.056 cm³ * 2.5 g/cm³ * 980 cm/sec²
= 109, 29, 587.2 dynes = 109.30 Newtons
c)
Weight of 60 liters of water = 60 kg
Total weight of aquarium with water = 169.30 newtons
d)
Pressure = Force on the table / Area of exterior at the bottom of aquarium
= 169.30 Newtons / (1.08 m * 0.48 m) = 326.581 Pa or N/m²
Here we are not considering the weight of atmosphere above aquarium.
e)
Hydrostatic pressure on the turtle = weight of water column at the bottom of aquarium
= 15.43 cm of water column * 1 gm/cm³ * 980 cm/sec²
= 15121.4 dyne = 0.151214 Pa
If the standard atmospheric pressure (of air above water level ) is to be added in addition to the hydrostatic pressure then, 1 atm is to be added.