Math, asked by shrey8050, 1 year ago

James went to a shop with $15 to buy chocolates. Each chocolate cost $1. There was a scheme in the shop that by returning 3 wrappers of the chocolates 1 chocolate is given free. Every chocolate has only 1 wrapper. How many chocolates can at maximum James eat ?

arunsinghrihal: 22 cocolates

arunsinghrihal: *chocolates

Answers

Answered by AntareepDey

At first James Bought 15 chocolates with15$

He returned all 15 wrappers and got 5 chocolates for free (15/3=5)

From these 5 chocolates, he returned 3 wrappers and got a chocolate for free.

Therefore he got a total number of (15+5+1=) 21 chocolates

ANSWER= 21 chocolates.

AntareepDey: Yeah right thanks

AntareepDey: I will edit my answer

shrey8050: He ate 15 chocolates returned 15 wrappers got 5 chocolates returned 3 wrappers left 2 wrappers got 1 chocolate and returned that 3 wrappers and got 1 chocolate more . ( 15 + 5 + 1 + 1 = 22 )

arunsinghrihal: lastly he is left with 5 wrappers ...with the 3 he will buy 1 chocolate...2 wrappers are already left and this chocolate's wrapper will also be counted so you again left with 3 wrappers

shrey8050: Yes good

shrey8050: Bye

arunsinghrihal: cool...was good riddle

arunsinghrihal: bye have fun

AntareepDey: Nice question @shrey8050 but if you already knew the answer, why did you post the question??

arunsinghrihal: he wanted to check that whether we will crack this or not...simple

Answered by Aanya599

HEY MATE HERE IS YOUR ANSWER:-

Total rupees = $15

1 chocolate cost = $1

So, James buy 15 chocolates by $1 because each chocolate cost is $1.

SCHEME = By returning 3 wrappers shopkeeper give 1 chocolate.

Chocolate = 15

According to scheme -

15÷3 = 5

NOW,

Total chocolate = 15+5

= 20

HOPE IT HELP YOU.

shrey8050: No very very wrong

Aanya599: Sorry

shrey8050: Answer is 22

Aanya599: Yes you are right

aryansharma2448: hi

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