Jamie wants to put tiles on the walls and floor of his room (but not on the ceiling). The length of his room is 10 feet, the width is 14 feet, and the height is 12 feet. If each tile is 1 foot long and 1 foot wide, how many tiles will Jamie need?
Answers
Answer:
716 tiles needed.
Step-by-step explanation:
The parameters of a room given in the question are
Length = 10 feet
Width = 14 feet
Height = 12 feet
and Jamie wants to put the tiles on walls and the floor of his room.
Dimensions of each tile
Length = 1 feet
width = 1 feet
Surface area of walls and floor = 4 walls + floor = 4(Area of one wall) + area of floor
= 2(Length×height + width×height) + (length×width)
= 2(10×12 + 14×12) + (10×14) = 2(120+168) + 140 = 2×288 + 140 = 576 +140 = 716
Now total number of tiles required = Total area to be covered/area of one tile
Number of tiles = 716/1 = 716
Therefore 716 tiles needed by Jamie.
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Jamie will need 716 tiles.
Step-by-step explanation:
Jamie wants to put tiles on the walls and floor of his room.
Length of his room = 10 feet
Width of his room = 14 feet
Height of the room = 12 feet.
Area of the floor = Length × width
= 10 × 14 = 140 feet²
As the room is rectangular shape so area of wall on width side is more than the area on length side.
Area of the wall on length side = length × height
= 10 × 12 = 120 feet²
There are two walls of same length = 120 × 2 = 240 feet²
Area of wall on width side = 14 × 12 = 168 feet²
Area of two opposite walls of same width = 168 × 2 = 336 feet²
Total area where Jamie wants to put tiles = 140 + 240 + 336
= 716 feet²
Each tile is 1 foot long and 1 foot wide, Hence Jamie will need 716 tiles.