Math, asked by yadavsnehasneha9336, 1 year ago

Jamila sold a table and a chair for 1050, thereby making a profit of 10% on the table and 25% on the chair.

Answers

Answered by najifaparveen16
16
''here is your answer''


Let the cost price of the table be Rs x and the cost price of the chair be Rs y.

The selling price of the table, when it is sold at a profit of 10% = Rs x + 10x/100 = 110x / 100

 

The selling price of the chair when it is sold at a profit of 25% = Rs y + 25y/100 = 125y / 100

 

So, 110x / 100 + 125y / 100 = 1050    ... (1)

 

When the table is sold at a profit of 25%, its selling price = Rs (x + 25x/100) = Rs 125x / 100

 

When the chair is sold at a profit of 10%, its selling price = Rs (y + 10y/100) = Rs 110y / 100

 

So, 125x / 100 + 110y / 100 = 1065   ... (2)

 

Solve (1) and (2), to get x = 500 and y = 400

 

Hence. the cost price of the table is Rs 500 and the cost price of the chair is Rs 400.

Answered by thamizhan12341234
1

Answer:

Step-by-step explanation:

Let the CPCP of chair and table be xxand yy respectively.

Given,

1050=110\%\times y+ 125\%\times x=1.1x+1.25y1050=110%×y+125%×x=1.1x+1.25y  

And

1050=110\%\times x+ 125\%\times y=1.1y+1.25x1050=110%×x+125%×y=1.1y+1.25x  

Solving above two equations,

we get,

x=400x=400 and y=500y=500

So, cost of chair=Rs.400=Rs.400.

and cost of table=Rs.500=Rs.500.

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