Question

jamin takes ₹10000 at 12 per year as rate of interest he has to pay at the end of two years?

step by step
please guys answer me fast ​

Answer 1

hope it helps u dear

Step-by-step explanation:

principal = rs 10,000

rate of interest = 12%

time = 2 yrs

amount = principal × ( 1 + R ÷ 100 ) ^ n

= 10,000 × ( 1 + 12 ÷ 100 ) ^ 2

= 10,000 × ( 1 + 3 ÷ 25 ) ^ 2

= 10,000 × ( 27 ÷ 25 ) ^ 2

= 10,000 × 27 ÷ 25 × 27 ÷ 25

= rs 11,664

answer = rs 11,664

Answer 2

Given :

• Rs. 10000
• Rate = 12 %

To find :

• Interest at the end of 2 years.

Solution :

Formula for Interest :

$\sf Simple\:Interest = \dfrac{P\:\times\:R\:\times\:T}{100}$

$\sf Simple\:Interest = \dfrac{\:10000\times\:12\:\times2\:}{100}$

Cutting the zeros :

$\sf \:Interest = \dfrac{100\times\:12\:\times2\:}{1}$

$\sf \:Interest = \dfrac{100\times\:12\:\times2\:}{1}$

$\sf Interest = 100 \times 12 \times 2$

Hence, Jamin has to pay Rs. 2400 at the end of 2 years.

Know more :-

• Simple Interest :

$\sf Simple\:Interest = \dfrac{P\:\times\:R\:\times\:T}{100}$