Question

Jammu Mail Departs From Ludhiana With The initial Velocity Of 24m/s , In 45 Seconds , Find The Acceleration Of Jammu Mail

Answer 1

Step-by-step explanation: Acceleration : V-u/t

                                           : 0-24/45

                                           : 0.5333 m/s^-2 is answer

Answer 2

Answer:

0.5333m/s^2

Step-by-step explanation:

initial velocity (u) = 24m/s,

finial velocity (v) = 0m/s,

time (t) = 45 seconds,

Acceleration (a) =?

Acceleration = final velocity - initial velocity / time

$a = \frac{v - u}{t}$

$= \frac{0 - 24m/s}{45s}$

= - 0.5333m/s^2

but , Acceleration cannot be in negative therefore

A = 0.5333m/s^2

I hope it helps you.

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