Question

Janae and Jerome each have m marbles. Gwen has 4(m + 2) marbles. John has 8m + 4 marbles. If John has more marbles than Janae, Jerome, and Gwen combined, how many marbles might Janae and Jerome each have? Select each possible answer.

Answer 1

Answer:

Let us take :

Janae = A

Jerome = B

Gwen = C

John = D

Given that

D > A + B + C

or, 8m + 4 > (m) + (m) + (4m + 8)

or, 8m + 4 > 6m + 8

or, 2m > 4

or, m > 2

Here, m belongs to the set of Natural numbers.

So, we can take

m = 3, 4, 5, ...

For example, we take m = 3.

Then, Janae has 3 marbles,

Jerome has 3 marbles,

Gwen has 20 marbles and

John has 28 marbles.

You can also put m = 4, 5, ... and you will get more answers.

Step-by-step explanation: