Question

Jane is 6 year older than her younger sister after 10 year the sum of their ages will be 50 years find their present ages

Answer 1

Let their present ages be
Jane : x + 6
younger sister : x

After ten years their ages will be
Jane : x + 6 + 10 = x + 16 (1)
younger sister : x + 10 (2)

Now given that sum of ages = 50
(1) + (2)
$x + 16 + x + 10 = 50 \\ 2x + 26 = 50 \\ 2x = 24 \\ x = 12$
Younger sister age is 12
Jane's age is 12+6 = 18

Answer 2

Let the present age of Jane's younger sister be x

Let The present age of Jane be x + 6

After 10 years the sum of their ages = 50 years

A/q,

[(x + 6) + 10] + [x + 10] = 50

[(x + 16) + (x + 10)] = 50

2x + 26 = 50

2x = 50 - 26

2x = 24

x = $\frac{24}{2}$

x = 12



Present age of Jane's younger sister = x = 12 years


Present age of Jane = x + 6 = 12 + 6 = 18 years