Question

Jane is 6 years older than her younger sister. After 10 years, the sum of their ages will be 50 years. Find the present ages.







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Answer 1

Answer:

Let their present ages be

Jane : x + 6

younger sister : x

After ten years their ages will be

Jane : x + 6 + 10 = x + 16 (1)

younger sister : x + 10 (2)

Now given that sum of ages = 50

(1) + (2)

Younger sister age is 12

Jane's age is 12+6 = 18

Answer 2

Answer:

Jane's age:- 18 years old

Younger sister's age:- 12 years old

Step-by-step explanation:

step by step solution is in picture