Question

Jane is 6 years older than her younger sister. After 10 years, the sum of their ages will be 50 years. Find Jane present ages.

Answer 1

Let sister's age is x

then jane's age = x+6

after 10 yrs sum of their age = 50yrs

x+(x+6)+10 = 50

2x +16 = 50

2x = 34

x = 17

x+6 = 23

hence jane's age = 23

& her younger sister's age = 17

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Answer 2

Answer:

Younger sister age is 12

Jane's age is 12+6 = 18

Step-by-step explanation:

Let their present ages be

Jane : x + 6

younger sister : x

After ten years their ages will be

Jane : x + 6 + 10 = x + 16 (1)

younger sister : x + 10 (2)

Now given that sum of ages = 50

(1) + (2)

Younger sister age is 12

Jane's age is 12+6 = 18