Question

Jane is 6 years older than her younger sister. After 10 years the sum of their ages will be 50 years. Find their present ages.​

Answer 1

Answer:

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Answer 2

Answer:

let jane's age be x and that of her younger sister be y.

hence, x=y+6...(jane is 6 years older than her sister)

x-y=6...(1)

according to given condition

(x+10)+(y+10)=50

x+y+20=50

x+y=50-20

x+y=30...(2)

adding equation (1)&(2)

2x=36

x=18

substituting x=18 in equation (1)

18-y=6

-y=6-18

-y=-12

y=12

Step-by-step explanation:

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