Math, asked by SamridhiNainwal, 5 days ago

Jane orders a party banner for his brother’s surprise birthday party. The length and width of the banner are 177.80 cm and 50.8 cm respectively.
(i) What is the area of the party banner?
(ii) Find the cost of the party banner if the cost is Rs.20per sq.cm.

Answers

Answered by akn0102
18

Answer:

(i) required area of the banner is 9032.24 cm^2

(ii) cost of the party banner is 180644.8 rupees

Step-by-step explanation:

in the question ,

length of the banner is , l = 177.80 cm

width of the banner is , w = 50.8 cm

then area of the banner is = l × w cm^2

= (177.80×50.8) cm^2

= 9032.24 cm^2

therefore required area of the banner is 9032.24 cm^2

if per cm square cost of the banner is 20 rupees

and also total area of the banner is 9032.24 cm^2

then total cost of the banner is (9032.24×20) = 180644.8 rupees

therefore cost of the party banner is 180644.8 rupees

Answered by fahims8080
25

Answer:

i) Area =9032.24cm^{2}  ii) 180644.80 Rupees

Step-by-step explanation:

According to the information provided in the question it is given as

Length of banner =l= 177.80cm

Width of banner = w=50.8 cm

We need to find the

(i) What is the area of the party banner?

(ii) Find the cost of the party banner if the cost is Rs.20per sq.cm.

A seen in the question it is clearly indicate that the banner is in the shape of rectangle so we find the area of rectangle

A = l\times w\\A = 177.80\times 50.8 \\A=9032.24cm^{2}

Now we find the cost of party banner = Area of banner x rate /cm^{2}

Putting the value we get the answer

Cost of banner = A \times Rate /cm^{2}

C =9032.24 \times 20\\C =180644.80 rupees

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