Question

Janice spent 3/8 of his money and had rupees 45 left.
how much did she have at first?​

Answer 1

Answer:

$let \: suppose \: jnice \: have \: x \: money$

Answer 2

Answer:

Step-by-step explanation:

Amount of money Janice had = 8/8

Amount of money she spent = 3/8

Amount of money she is left with = 8/8 - 3/8 = 5/8

Now since it is written that 45 rupees are left with her so,

Let the total amount of money janice had be x.

Then,

5/8 × x = 45

x = 45 × 8/5

x = 72