Question

jannet gave 5/8 coins to karen if she gabe 250 old coins to karen how many coins did she have at first​

Answer 1

Answer:

Let's assume that she originally have x coins,

She gave 5/8 of x to Karen

i.e  

$\frac{5}{8}x = 250$

5x = 8 * 250

5x = 2000

x = 400

She have 400 coins initially.

Answer 2

Therefore, Jannet have $400$ coins at first.

Step-by-step explanation:

Given;

Jannet gave $\frac{5}{8}$ coins to karen and she gave $250$ coin to karen.

Let,

Jannet have $x$ coins at first.

From given construction,

∴$\frac{5}{8}\times x=250$

⇒$x=250\times \frac{8}{5}$

⇒$x=50\times 8$

∴$x=400$

So, Jannet have $400$ coins at first.