Jar a contains 8 litres of a solution of ethanol and methanol in the ratio of 9:11 Respectively. Jar b contains 10 litres of a solution of ethanol and ethanol in the ratio 13:12
Answers
For jar A Ethanol :Methanol =3.6:4.4 for jar B Ethanol :Methanol =5.2:4.8
22 : 23 would be the ratio of ethanol and methanol if both jars mixed together
Step-by-step explanation:
Jar a contains 8 litres of a solution of ethanol and methanol in the ratio of 9:11
Jar a
Ethanol = (9/20)*8 = 72/20 = 18/5
Methanol = (11/20)*8 = 22/5
Jar b contains 10 litres of a solution of ethanol and ethanol in the ratio 13:12
Jar b
Ethanol = (13/25)*10 = 26/5
Methanol = (12/25)*10 =24/5
Ethanol = 18/5 + 26/5 = 44/5
Methanol = 22/5 + 24/5 = 46/5
44/5 : 46/5
= 44 : 46
= 22 : 23
22 : 23 would be the ratio of ethanol and methanol if both jars mixed together
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