jar contains 2 blue 3red 5 yellow and 4 green Marbles if a marble is drawn at random from the jar what is the probability that the marble drawn is not read.
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plz solve the question with step by step explanation
Answers
Answered by
2
Marbles contain 2 blue, 3 red, 5 yellow and 4 green balls.
POSSIBLE OUTCOMES = 2+3+5+4 = 14
FAVOURABLE OUTCOMES = SUM OF NUMBERS OF TOTAL BALLS - RED BALLS = 11-3 = 9
P(E) GETTING A BALLS IS NOT RED = POSSIBLE OUTCOMES/FAVOURABLE OUTCOMES = 14/9
POSSIBLE OUTCOMES = 2+3+5+4 = 14
FAVOURABLE OUTCOMES = SUM OF NUMBERS OF TOTAL BALLS - RED BALLS = 11-3 = 9
P(E) GETTING A BALLS IS NOT RED = POSSIBLE OUTCOMES/FAVOURABLE OUTCOMES = 14/9
Answered by
1
Answer:
The answer is 11/14
Step-by-step explanation:
Total no.of marbles= 2+3+5+4=14
left the red ball so remain ball =11
So,11/14is the answer
And please mark me brainleast
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