Question

जर M = { 3, 6, 9, 12, 15, 18 } तर n(M) = ककती? (A) 5 (B) 6 (C) 4 (D) 7​

Answer 1

Answer:

324

The given number = 324

For a number to be divisible by 6 it should be divisible by both 2 and 3 .

Sum of its digits = 3 + 2 + 4 = 9

Since 9 is divisible by 3 therefore the number is divisible by 3 and unit digit is divisible by 2 so it is divisible by 2.

Thus, 324 is divisible by 6.

(ii) 2010

The given number = 2010

For a number to be divisible by 6 it should be divisible by both 2 and 3

Sum of its digits = 2 + 0 + 1 + 0 = 3

Since 3 is divisible by 3 therefore the number is divisible by 3 and unit digit is divisible by 2 so it is divisible by 2.

Thus, 2010 is divisible by 6.

(iii) 33278

The given number = 33278

For a number to be divisible by 6 it should be divisible by both 2 and 3 .

Sum of its digits = 3 + 3 + 2 + 7 + 8 = 23

Since 23 is not divisible by 3 therefore the number is not divisible by 3 and unit digit is divisible by 2 so it is divisible by 2.

Thus, 33278 is not divisible by 6.

(iv) 15505

The given number = 15505

For a number to be divisible by 6 it should be divisible by both 2 and 3

Sum of its digits = 1 + 5 + 5 + 0 + 5 = 16

Since 16 is not divisible by 3 therefore the number is not divisible by 3 and unit digit is not divisible by 2 so it isnot divisible by 2.

Thus, 15505 is not divisible by 6.