जर तर पुढील गुणाेत्तरांच्या किंमत काढा:
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Given,
a/b = 7/3
Let's, represent b in terms of a,
a = 7/3*b...(1)
Given equation,
{a^3-b^3}/b^3....(2)
Putting value of a from (1) in (2),
= {(7/3)^3*b^3}-b^3/b^3
b^3 gets cancel out from the above equation ⤴,
So,
= (343/81 - 1)/1
= 343-81/81
= 262/81
= 3.23 (aprox)
In these types of question, just observe the common terms and cancel them so to make the equation more easy for the solving process.
Just remember to express the second term in terms of first so to get a clear picture for solving.
a/b = 7/3
Let's, represent b in terms of a,
a = 7/3*b...(1)
Given equation,
{a^3-b^3}/b^3....(2)
Putting value of a from (1) in (2),
= {(7/3)^3*b^3}-b^3/b^3
b^3 gets cancel out from the above equation ⤴,
So,
= (343/81 - 1)/1
= 343-81/81
= 262/81
= 3.23 (aprox)
In these types of question, just observe the common terms and cancel them so to make the equation more easy for the solving process.
Just remember to express the second term in terms of first so to get a clear picture for solving.
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