Question

जर $\frac{y+z}{a}=\frac{z+x}{b} =\frac{x+y}{c}$ तर $\frac{x}{b+c-a}=\frac{y}{c+a-b} =\frac{z}{a+b-c}$ हे दाखवा.

Answer 1

Answer:

Step-by-step explanation:

(y+z)/a = (z+x)/b = (x+y)/c = k

y+ z = ak

z + x =bk

x + y = ck

bk + ck - ak = z + x+ x + y -y -z

k (b +c-a) = 2x

x/(b+c-a) = k/2

k(c + a -b)= 2y

y/(c+a-b) = k/2

ak + bk -ck = y+z + z+x -x-y

k(a+b-c) = 2z

z/(a + b -c) = k/2

as all comes equal to k/2

hence proved

x/(b+c-a) = y/(c+a-b) = z/(a + b -c)