Math, asked by HarshadaDilipBagul, 1 month ago

जर x=-1 हे 5x²+kx-7=0 या समीकरणाचे एक मूळ असेल तर k ची किंमत काढा. ​

Answers

Answered by vatsarun58
5

Answer:

k= -12

Step-by-step explanation:

5x {}^{2}  + kx + 7 = 0 \\ 5(1) {}^{2}  + k(1) + 7 = 0 \\ 5 + k + 7 = 0 \\ k + 12 = 0 \\ k =  - 12

Answered by vishalkamble67
1

k=-2

Step-by-step explanation:

x =-1 ही किंमत समीकरणात भरू

5क्स(-1

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