Math, asked by sanjayshinde1711968, 6 months ago

जर x=3 हे kx2-10x+3=0 या समीकरणो एक मूळ असेल, तर K ची किंमत काढा.

Answers

Answered by sambhunathcc9

16

Answer:

kx2-10x+3=0

k(3×2)-10×3+3=0

k6-30+3=0

k27=0

k=27

Answered by asinde67

0

Answer:

kx2-10x+3=0 (Bx2) -10x3+3=10 k6-30+3=0 k27=0 k=27

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