Question

*जर x² + 4x + 10 / 2x + 5 = x² + 8x + 20 / 4x + 10 तर x = ?*
1️⃣ 2.5 आणि 0
2️⃣ 3 आणि 0
3️⃣ -3 आणि 0
4️⃣ -2.5 आणि 0

Answer 1

Given :- if x² + 4x + 10 / 2x + 5 = x² + 8x + 20 / 4x + 10 , find x = ?

Solution :-

→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / (4x + 10)

taking 2 common from RHS denominator,

→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / 2(2x + 5)

(2x + 5) will be cancel from both sides denominator,

→ 2(x² + 4x + 10) = x² + 8x + 20

→ 2x² + 8x + 20 = x² + 8x + 20

→ 2x² - x² + 8x - 8x + 20 - 20 = 0

→ x² = 0

→ x = 0 .

now, again,

→ (x² + 4x + 10) / (2x + 5) = (x² + 8x + 20) / (4x + 10)

multiply by (1/2) both sides ,

→ (x² + 4x + 10) / (4x + 10) = (x² + 8x + 20) / (8x + 20)

using divindo now, we get,

→ [(x² + 4x + 10) - (4x + 10)] / (4x + 10) = [(x² + 8x + 20) - (8x + 20)] / (8x + 20)

→ x²/(4x + 10) = x²/(8x + 20)

x² will be cancel from both sides,

→ 1/(4x + 10) = 1/(8x + 20)

→ 4x + 10 = 8x + 20

→ 8x - 4x = 10 - 20

→ 4x = (-10)

→ x = (-2.5) .

Hence, value of x will be (-2.5 and 0.)

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