Question

Jason and Kyle both choose a number from 1 to 10 at random. What is the probability that both numbers are odd?

Answer 1

n(S) = 10

P(A) = n(A)/n(S)

A = [Odd numbers]

A = [1,3,5,7,9]

n(A) = 5

P(A) = 5/10

P(A) = 1/2

Answer 2

sample space = { 1 , 2 , 3 , 4, , 5 , 6 , 7 , 8 , 9 , 10 }

Let 'A' be the probability of odd numbers.

odd numbers are 1 , 3 , 5 , 7 , 9.

5P(A) = n(A) / n(s) = 5 / 10
= 1 / 2