Question

Jason and Terrence shared a box of marbles in the ratio 7 : 4. When Jason gave half of his share to Terrence, and Terrence had 32 marbles more than Jason. How many more marbles did Jason have than Terrence at first?​

Answer 1

Answer:

44 is the answer hope its help u

Answer 2

24 many more marbles did Jason have than Terrence at first.

 Given:

Jason Terrence shared a box of marbles in the ratio of 7:4

Number of Marbles Jason have $=7x$

Number of Marbles Terrence have $=4x$

Jason gave half of his share to Terrence

we get, Jason$=\frac{7x}{2}$

Terrence $=4x+\frac{7x}{2}$

To find:

Number of marbles did Jason have than Terrence at first.

Step-by-step explanation:

Then Terrence had 32 marbles more than Jason.

from we get,

$4x+\frac{7x}{2}=32+\frac{7x}{2}\\\\\frac{8x+7x}{2}=\frac{64+7x}{2}\\\\8x=64\\\\x=8$

Substitute x in 7x and 4x

we get, at first Jason and Terrence value

Jason $=7\times\ 8=56$

Terrence $=4\times\ 8=32$

To find the difference of marbles Jason and Terrence have,

$56-32=24$

Hence At first,24 marbles Jason have more than Terrence.