Question

Jason goes scuba diving in honduras, where the density of the water in the ocean is 1025 kg/m . Assuming the pressure of the air is 1.0 atm, what is the pressure when jason is 16.9 m below the surface? Give your answer in units of atm. Hint1: recall that 1 atm 101.3 kpa

Answer 1

P= atm(P)+ρgh

P= 101300+ 1025×9.8×16.9

P= 101300+169760.5

P = 271060.5 Pa

P = 271060.5/101300

P== 2.676 atm