Jason goes scuba diving in honduras, where the density of the water in the ocean is 1025 kg/m . Assuming the pressure of the air is 1.0 atm, what is the pressure when jason is 16.9 m below the surface? Give your answer in units of atm. Hint1: recall that 1 atm 101.3 kpa
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P= atm(P)+ρgh
P= 101300+ 1025×9.8×16.9
P= 101300+169760.5
P = 271060.5 Pa
P = 271060.5/101300
P== 2.676 atm
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