Jaspal donates \left(\frac{1}{5}\right)^{t h} part of his monthly income and deposited \left(\frac{1}{6}\right)^{t h} part in the bank and expenditure the remaining income.
Answers
Given : Jaspal donates 1/5part of his monthly income
deposited 1/6 part in the bank
expenditure the remaining income.
To Find : expenditure
Solution:
Assume that Total Income = 30A
donates 1/5part of his monthly income = (1/5)30A = 6A
deposited 1/6 part in the bank = (1/6)30A = 5A
Donated = 6A
Deposited = 5A
Total = 30A
Remaining = 30A - 6A - 5A
= 19A
Expenditure = 19A
Expenditure compared to total = 19A/30A = 19/30
expenditure = 19/30 th part
or Directly
1 - 1/5 - 1/6
= 30/30 - 6/30 - 5/30
= (30 - 6 - 5)/30
= 19/30
expenditure = 19/30 th part
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