Math, asked by abhishek12359, 3 months ago

Jaspal started walking from his house to office. Instead of going to office directly, he

goes to a bank first, from there to his daughter’s school, and then reaches the office.

What is the extra distance travelled by Jaspal in reaching office, if the house is situated

at (2, 4), bank at (5, 8), school at (13, 14) and office at (13, 26).​

Answers

Answered by suyoggogawale123
2

Answer:

Given

House is situated at H(2,4)

Bank is situated at B(5,8)

School is situated at S(13,14)

Office is situated at O(13,26)

By distance formula

HO=

(13−2)

2

+(26−4)

2

HO=

121+484

=

605

HO=24.59km

HB=

(5−2)

2

+(8−4)

2

HB=

9+16

=

25

HB=5km

BS=

(13−5)

2

+(14−8)

2

BS=

64+36

=

100

BS=10km

SO=

(13−13)

2

+(26−14)

2

SO=

144

SO=12km

Total distance travelled by Ayush is =HB+BS+SO

Total=5+10+12=27km

Distance between office and house is 24.59km

Hence Extra distance =27−24.59=2.41km

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