Question

jate the following:
(1 + tan 0 + sec 0) (1 + coto - cosec )
cos A)2 + (sin 0 - cos 0)?​

Answer 1

Answer:

hope it helps u please please mark me brainliest please please

Step-by-step explanation:

According to given sum,

sin (1+tan)+cos (1+cot)=sec+cosec

=> LHS= sin (1+tan)+cos (1+1/tan)

=> sin (1+tan)+cos (1+tan)/tan

=> (1+tan)(sin+cos/tan)

=> (1+tan)(sin.tan+cos)/tan

=> (1+tan)(sin^2/cos+cos)/tan

=> (1+tan)(sin^2+cos^2)/tan.cos

=>(1+tan)/tan.cos

=>(1/tan.cos)+tan/tan.cos

=>( cot/cos)+(1/cos)

=> cosec +sec

LHS= RHS.

Like my answer if you find it useful!