Question

java menu driven program to check whether the given no. is armstrong or not​

Answer 1

Answer:

$Answer : class ArmstrongExample{ </p><p> public static void main(String[] args) { </p><p> int c=0,a,temp; </p><p> int n=153;//It is the number to check armstrong </p><p> temp=n; </p><p> while(n>0) </p><p> { </p><p> a=n%10; </p><p> n=n/10; </p><p> c=c+(a*a*a); </p><p> } </p><p> if(temp==c) </p><p> System.out.println("armstrong number"); </p><p> else </p><p> System.out.println("Not armstrong number"); </p><p> } </p><p>}$