Question

Java program to calculate sum of series (1+2)/(1*2)+(1+2+3)/(1*2*3)+------(1+2+3+------n)/(1*2*3*4-------n)

Answer 1

ANSWER
............



#include<stdio.h>

int main(){

int n,sum,sum1=0,i,j;

printf("Please enter an integer n=");

scanf("%d",&n);

for(i=1;i<=n;i++){

sum=0;

for(j=1;j<=i;j++)

sum=sum+j;

sum1=sum1+sum;

}

printf("The sum of the series=%d\n",sum1);

return 0;

Answer 2

C++
// C++ program to find the sum of given series

#include <bits/stdc++.h>

using namespace std;

 

// function to find the sum of given series

double sumOfTheSeries(int n)

{

    // Computing sum term by term

    double sum = 0.0;

    for (int i = 1; i <= n; i++)

        sum += 1.0 / (i * (i + 1));  

    return sum;

}

 

// driver program to test above function

int main()

{

    int n = 10;

    cout << sumOfTheSeries(n);

    return 0;

}

java

class demo {

 

    // function to find the sum of given series

    public static double sumOfTheSeries(int n)

    {

       // Computing sum term by term

        double sum = 0.0;

        for (int i = 1; i <= n; i++)

            sum += 1.0 / (i * (i + 1));

        return sum;

    }

 

    // driver program to test above function

    public static void main(String args[])

    {

        int n = 10;

        System.out.println(sumOfTheSeries(n));

    }

}