Question

(JAVA)- Programs om
(1) Accept a number
and display whether it is an even number or odd number
Give answer as fast as possible​

Answer 1

In the following example we have provided the value of n as 100 so the program will print the odd numbers from 1 to 100.

The logic we are using in this program is that we are looping through integer values from 1 to n using for loop and we are checking each value whether the value%2 !=0 which means it is an odd number and we are displaying it. To understand this program, you should have the basic knowledge of for loop and if statement.

class JavaExample {

public static void main(String args[]) {

int n = 100;

System.out.print("Odd Numbers from 1 to "+n+" are: ");

for (int i = 1; i <= n; i++) {

if (i % 2 != 0) {

System.out.print(i + " ");

}

}

}

}

Output:

Odd Numbers from 1 to 100 are: 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29

31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77

79 81 83 85 87 89 91 93 95 97 99

Answer 2

Explanation:

Now, to check whether num is even or odd, we calculate its remainder using % operator and check if it is divisible by 2 or not.

For this, we use if...else statement in Java. If num is divisible by 2, we print num is even. Else, we print num is odd.

We can also check if num is even or odd by using ternary operator in Java.

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