Question

Javid and munish went to a tea party of thier friend sameena.Sameena's mother offerd to all the friends a big britannia cake having 24 pieces.Javid ate 2/6 of the cake,sameena ate 1/12 of the cake and munish ate 1/4 of the cake.How much pieces each took?What fraction of the total remained?

Answer 1

Cake pieces eaten by each :-

1. Javid = 8 Pieces
2. Sameena = 2 Pieces
3. Munish = 6 Pieces

• Total Number of Pieces Consumed = 16 Pieces
• $Left \: Pieces = 8 Pieces = \frac{2}{6}$

Answer 2

Javid took 8 pieces and Sameena took 2 pieces and Munish took 6 pieces

1/3 of the total remained

Solution:

Total = 24 pieces

Javid ate 2/6 of the cake

Therefore,

$Javid = \frac{2}{6} \times 24\\\\Javid = 8$

Sameena ate 1/12 of the cake

$Sameena = \frac{1}{12} \times 24\\\\Sameena = 2$

munish ate 1/4 of the cake

$Munish = \frac{1}{4} \times 24\\\\Munish = 6$

Total Number of Pieces Consumed = 8 + 2 + 6 = 16

Left = 24 - 16 = 8

Thus, fraction of the total remained is:

$\frac{8}{24} = \frac{1}{3}$

Thus 1/3 of the total remained

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