Question

Jayanti throws a pair of dice and records the product of the numbers appearing on the dice. Pihu throws 1 dice and records the squares the number that appears on it. Who has the better chance of getting the number​

Answer 1

Step-by-step explanation:-

Given  

Jayanti throws a pair of dice and records the product of the numbers appearing on the dice. Pihu throws 1 dice and records the squares  the number that appears on it. Who has the better chance of getting the number​

• Let S be the event containing all possibilities that occur when Jayanti throws a pair of dice.
• So the total outcomes will be 6 x 6 = 36 outcomes.
• Therefore n(S) = 36
• Let A be the event such that Jayanti will get the product of numbers appearing on dices as 36
• Since there is only one probability (6,6) to get the product 36 we have n(A) = 1
• Therefore the probability of getting product of numbers appearing on the dice as 36 is P (A) = n(A) / n(S) = 1/36
• Now let S be the event that contains all possibilities that Pihu gets after throwing 1 dice.
• Therefore n(S’) = 6
• Let B be the event such that Pihu will get square of the number appearing on the dice as 36
• We know the square of only one possibility 6 is 36.
• Therefore n(B) = 1
• So probability of getting square of number will be
• P (B) = n(B) / n(S’) = 1/6
• Since 1/6 > 1/36,

Pihu has a better chance of getting the number 36.

Reference link will be

https://brainly.in/question/12623482