Jeanette obtained 32% for her statistics test, which was out of a total of 300 marks. How much should she score in the computer science test that is out of 200 marks in total if she is to get a proportionally weighted average of 46%?
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Answers
Answer:
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Given: Jeanette obtained 32% for her statistics test, which was out of a total of 300 marks.
To find: Marks that she should score in the computer science test that is out of 200 marks in total if she is to get a proportionally weighted average of 46%
Explanation: Marks scored in statistics test by Jeanette= 32% of 300
= 32*300 /100
= 96 marks
Total marks of statistics test and computer science test= 300+200
= 500 marks
Total marks to get 46% of 500 marks
= 46*500/100
= 230 marks
Therefore, 230 marks should be scored in total to get 46% out of 500 marks.
Marks that should be scored in Computer Science test
=Total marks to get 46% - marks scored in statistics
= 230 - 96
= 134 marks
Therefore, Jeanette should score 134 marks out of 200 in her Computer Science test to get a proportionally weighted average of 46%.