Question

jee
3
If the density of liquid water is 1.0 g cm
and that of water vapour is
0.0006 cm at 100°C and 1 atm, then the volume occupied by water
molecules in 1 litre of steam at this temperature is
ka) 6 cm
(b) 60 cm
(c)
0.6 cm
(d) 0.06 cm

Answer 1

Answer:

0.6 cm3

Explanation:

Let us consider, 1.0 L of liquid water is converted into steam volume of H2O (l) = 1 L, mass = 1000 g ⇒ Volume of 1000 g steam = (1000 )/0.0006 cm3 ∵ Volume of molecules in (1000 )/0.0006 cm3 steam = 1000 cm3 ∴ Volume of molecules in 1000 cm3 steam = (1000 )/1000 × 0.0006 × 1000 = 0.60 cm3

Answer 2

$\pink{\huge{\underline{\underline{♡Answer♡}}}}$

HEAT = I²RT

I×IRT

SINCE, V = IR

HEAT = IVT

220 = V/R × VT

220 = V²T/R

220×8/1 = V²

v = $\sqrt{220 \times 8}$

V = 42