Question

JEE (Adv.) Level Question:
If
$g(x) \: = {e}^{2x} + {e}^{x} - 1$
and
$h(x) = {3x}^{2} - 1$
the value of
$g(h(0))$
is?

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Answer 1

Step-by-step explanation:

Given that: If

$g(x)=e^{2x}+e^x-1\\\\h(x)=3x^2-1$

To find: Value of

$g(h(0))$

Solution: To find

$g(h(0))$

First of all find

$goh(x)=e^{(2[3x^2-1])}+e^{(3x^2-1)}-1$

Now put zero at the place of x

$goh(0)=e^{(2[3(0)^2-1])}+e^{(3(0)^2-1)}-1$

$goh(0)=e^{(2[-1])}+e^{((-1)}-1$

$goh(0)=e^{-2}+e^{-1}-1$

Hope it helps you