Question

❌Jee advance ❌
(Multiple correct option )
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Position of a particle in rectilinear motion is given by s = t³-6t²+9t

correct option for this particle are .
(a) total displacement of particle in first 5s is 20m

(b) total distance travelled by particle in first 5sec is 28m

(c) particle is moving at t = 1sec and t = 3sec

(d) acceleration of particle is constant .​

Answer 1

Answer:

ONCE PLEASE REFER THESE TWO PHOTOS

HOPE IT HELPS YOU

Answer 2

Answer : (a,b)

explanation:-velocity of particle is

V = ds/dt = 3t²-13t+9

= 3(t-1)(t-3)

Now , (t-1)(t-3) is positive when (t-1) and (t-3)both are positive or both are negative , i.e particle moves in positive direction when t< 1 or t>3

in interanal 1<t<3 position moves backward

so , distance travelled by particle in first 5sec = 4+4+20 = 28m

also displacement in first 5 sec = 20m

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